this post was submitted on 26 Aug 2023
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    101
    Which way do you expand variables? (lemmy.world)
    submitted 1 year ago by zephyr@lemmy.world to c/linuxmemes@lemmy.world
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    [–] RazorsLedge@lemmy.world 22 points 1 year ago* (last edited 1 year ago) (1 children) 
    foo=ding
foobar=dong

echo \$foobar

    Brackets make it explicit what you're trying to do. Do you want "dingbar" or do you want "dong"? I forget what the actual behavior is if you don't use brackets here, because I always use brackets for this reason now

    [–] subtext@lemmy.world 5 points 1 year ago (1 children)

    I believe the actual behavior here would be printing “dong” as the shell interpreter is greedy in its evaluation of variables.

    [–] vrighter@discuss.tchncs.de 2 points 1 year ago (1 children)

    the actual behavior here is to echo the literal string "$foobar", because the $ sign is escaped. so no variable expansion will take place at all.

    [–] RazorsLedge@lemmy.world 2 points 1 year ago (2 children)

    Oh lol. It doesn't show the $ at all on my mobile app till I escaped it

    [–] vrighter@discuss.tchncs.de 2 points 1 year ago

    ah, so it's up to the client. I'm using jerboa, in this case

    [–] rtxn@lemmy.world 1 points 1 year ago (1 children)

    You should use markdown's inline code (single `backtick`) and

    block code
(triple backtick)

    tags. They are consistent across most markdown renderers (except Reddit's, which uses four-space indentations (like, who the fuck thought that was a good idea?))

    [–] RazorsLedge@lemmy.world 1 points 1 year ago

    I did use triple backticks