this post was submitted on 01 Feb 2025
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[–] thevoidzero@lemmy.world 6 points 1 day ago (1 children)

I downloaded it yesterday to test, and my wife was immediately was like ask about it. I had to comply, it said I can't talk about sensitive topic, but in the think it talked a bit.

Anyway, I tested simple sum, good job. I tested an integration that doesn't have closed form solution poor thing was thinking a lot, everytime it goes "this happened which makes the integral impossible" then it goes "maybe another approach" and tries again. Had to ctrl+C, but I'm at least impressed with trying to find solution without giving up, very asian.

[–] Unbecredible@lemm.ee 2 points 1 day ago (1 children)

What was the integral and what form does a solution take when there's no closed form?

I'm curious because I used to know but forgot most of calculus at this point.

[–] thevoidzero@lemmy.world 2 points 1 day ago* (last edited 1 day ago) (1 children)

Integration was this (idk if lemmy renders latex):

int_0^1{x^{-1} (1-x)^{n-1}} dx

[ \int_0^1 {x^{-1} (1-x)^{n-1}}dx ]

Text: finite integration from 0 to 1 of function x to power negative one, (1-x) to the power (n-1).

The limit at 0 goes to infinity that's why there is no solution. But deepseek kept trying different method reaching a conclusion that it can't be solved then then trying different approach.

About the closed form, the function without closed form was that function multiplied by x^y (1-x)^y .

int_0^1{x^{y-1} (1-x)^{n-y-1}} dx

The first one is a case where y=0. Unless y=0 or n, you have integration, just not a closed form. You can plot the function to see it as well. You'd have to try different values of y and n for it to actually plot something though.

[–] Unbecredible@lemm.ee 2 points 21 hours ago

Ah I see thank you