this post was submitted on 04 Dec 2023
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Advent Of Code

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An unofficial home for the advent of code community on programming.dev!

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

AoC 2023

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Day 4: Scratchcards


Megathread guidelines

  • Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
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[–] Ategon@programming.dev 1 points 9 months ago* (last edited 9 months ago) (1 children)

[JavaScript] Swapped over to javascript from rust since I want to also practice some js. Managed to get part 1 in 4 minutes and got top 400 on the global leaderboard. Second part took a bit longer and took me 13 mins since I messed up by originally trying to append to the card array. (eventually swapped to keeping track of amounts in a separate array)

Part 1

// Part 1
// ======

function part1(input) {
  const lines = input.split("\n");
  let sum = 0;

  for (const line of lines) {
    const content = line.split(":")[1];
    const winningNums = content.split("|")[0].match(/\d+/g);
    const myNums = content.split("|")[1].match(/\d+/g);

    let cardSum = 0;

    for (const num of winningNums) {
      if (myNums.includes(num)) {
        if (cardSum == 0) {
          cardSum = 1;
        } else {
          cardSum = cardSum * 2;
        }
      }
    }

    sum = sum + cardSum;
  }

  return sum;
}

Part 2

// Part 2
// ======

function part2(input) {
  let lines = input.split("\n");
  let amount = Array(lines.length).fill(1);

  for (const [i, line] of lines.entries()) {
    const content = line.split(":")[1];
    const winningNums = content.split("|")[0].match(/\d+/g);
    const myNums = content.split("|")[1].match(/\d+/g);

    let cardSum = 0;

    for (const num of winningNums) {
      if (myNums.includes(num)) {
        cardSum += 1;
      }
    }

    for (let j = 1; j <= cardSum; j++) {
      if (i + j >= lines.length) {
        break;
      }
      amount[i + j] += amount[i];
    }
  }

  return lines.reduce((acc, line, i) => {
    return acc + amount[i];
  }, 0);
}

Code Link

[–] Ategon@programming.dev 1 points 9 months ago* (last edited 9 months ago)

Improvement I found afterwards:

  • Could have done a reduce on the amount array instead of the lines array since I don't use the line value at all