this post was submitted on 06 Dec 2023
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Advent Of Code

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An unofficial home for the advent of code community on programming.dev!

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

AoC 2023

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Day 6: Wait for It


Megathread guidelines

  • Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
  • Code block support is not fully rolled out yet but likely will be in the middle of the event. Try to share solutions as both code blocks and using something such as https://topaz.github.io/paste/ , pastebin, or github (code blocks to future proof it for when 0.19 comes out and since code blocks currently function in some apps and some instances as well if they are running a 0.19 beta)

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[โ€“] reboot6675@sopuli.xyz 2 points 7 months ago (1 children)

Golang

Pretty straightforward. The only optimization I did is that the pairs are symmetric (3ms hold and 4ms travel is the same as 4ms hold and 3ms travel).

Part 1

file, _ := os.Open("input.txt")
defer file.Close()
scanner := bufio.NewScanner(file)

scanner.Scan()
times := strings.Fields(strings.Split(scanner.Text(), ":")[1])
scanner.Scan()
distances := strings.Fields(strings.Split(scanner.Text(), ":")[1])
n := len(times)
countProduct := 1

for i := 0; i < n; i++ {
	t, _ := strconv.Atoi(times[i])
	d, _ := strconv.Atoi(distances[i])
	count := 0
	for j := 0; j <= t/2; j++ {
		if j*(t-j) > d {
			if t%2 == 0 && j == t/2 {
				count++
			} else {
				count += 2
			}
		}
	}

	countProduct *= count
}

fmt.Println(countProduct)

Part 2

file, _ := os.Open("input.txt")
defer file.Close()
scanner := bufio.NewScanner(file)

scanner.Scan()
time := strings.ReplaceAll(strings.Split(scanner.Text(), ":")[1], " ", "")
scanner.Scan()
distance := strings.ReplaceAll(strings.Split(scanner.Text(), ":")[1], " ", "")

t, _ := strconv.Atoi(time)
d, _ := strconv.Atoi(distance)
count := 0

for j := 0; j <= t/2; j++ {
	if j*(t-j) > d {
		if t%2 == 0 && j == t/2 {
			count++
		} else {
			count += 2
		}
	}
}

fmt.Println(count)

[โ€“] morrowind@lemmy.ml 2 points 7 months ago

ah damn, didn't think of the symmetric pairs