What about something like this:
for i in /media/johann/5461-000B/DCIM/100MEDIA/*.AVI; do newpath="$HOME/Public/240321/$(basename "$i" | sed 's/^IMAG/240321_/g')"; ffmpeg -i "$i" -ss 00:00:00 -t 00:00:20 "$newpath" && rm "$i"; done
this post was submitted on 21 Mar 2024
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Awesome! Thanks, I knew there had to be a way!
edit:
This also works:
for i in *.avi; do ffmpeg -i "$i" -ss 00:00:00 -t 00:00:10 ~/Public/test/${i%.*}.avi ; done
But yours is much nicer.
Try this:
for file in ./*
do
echo "$file"
done
To do some substitution operation om the filename you can use Bash Parameter Expansion.
Use another folder instead of name
The input filename changes each time.
find -name "*.avi" | while read file;
do
echo -v "$file"
done
edited
Almost, here is the one that worked:
for i in *.avi; do ffmpeg -i "$i" -ss 00:00:00 -t 00:00:10 ~/Public/test/${i%.*}.avi ; done
Thanks for pointing me in the right direction.