this post was submitted on 08 Sep 2024
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No Stupid Questions

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I would have asked this on a math community but I couldn't find an active one.

In a spherical geometry, great circles are "straight lines". As such, a triangle can have two or even three right angles to it.

But what if you go the long way around the back of the sphere? Is that still a triangle?

(Edit:) I guess it's a triangle! Fair enough; I can't think of what else you would call it. Thanks, everyone.

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[–] towerful@programming.dev 8 points 2 months ago (3 children)

What if it had 3 corners and 4 edges? Or 4 corners and 3 edges?

[–] RightHandOfIkaros@lemmy.world 21 points 2 months ago* (last edited 2 months ago) (1 children)

If a shape has 3 corners and 4 edges, it is incomplete or open and therefore not a shape yet but a collection of edges (or possibly, two triangles that share an edge).

A shape with 4 corners and 3 edges is not possible. An edge cannot have a corner in the middle of it, that would make it two edges.

[–] towerful@programming.dev 2 points 2 months ago

I felt like adding something about the specific case of 180° between edges and a vertice.
Makes sense.
And I guess too many vertices means an open set of edges (ie not close, this not a shape).
I was kinda hoping for a strange edge case, like a mobius strip or Klein bottle.

I guess a mobius strip is a 2d representation of a 1d paradigm. And a klein bottle is a 3d representation of a 2d paradigm.
It would be too much to ask of a 1d representation of a ??d paradigm.

[–] ByteJunk@lemmy.world 5 points 2 months ago (2 children)

Why the down votes? Bro asking a question and being legit curious, don't be hating on someone that's looking to challenge what they know just because it's trivial to you.

[–] towerful@programming.dev 4 points 2 months ago

I feel my comment adds to the discussion and wants more details.
But it was too simply phrased.
I guess the details of such a question should be obvious. And if you need the details, the question doesn't actually add the the discussion... It just seems idiotic!

I felt like there might be a really cool scenario where a vertice isn't considered a vertice.
Like, there actually might be some case on a 2d plane "where actually" applies.
I'm fine being wrong

[–] RightHandOfIkaros@lemmy.world 1 points 2 months ago

Welcome to Lemmy, first time?

[–] november@lemmy.vg 3 points 2 months ago (1 children)

I don't think that can be a thing.

[–] towerful@programming.dev 2 points 2 months ago

Yeh, seems not