this post was submitted on 15 Nov 2023
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submitted 1 year ago by mac@programming.dev to c/programmer_humor@programming.dev
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[–] dannym@lemmy.escapebigtech.info 3 points 1 year ago* (last edited 1 year ago) (3 children)

Definitely, tho if you store it as a u32 that is fixed magically. Because 1.2.3.4 and 1.02.003.04 both map to the same number.

What I mean by storing it as a u32 is to convert it to a number, similar to how the IP gets sent over the wire, so for v4:

octet[3] | octet[2] << 8 | octet[1] << 16 | octet[0] << 24

or in more human terms:

(fourth octet) + (third octet * 256) + (second octet * 256^2) + (first octet * 256^3)
[–] p1mrx@sh.itjust.works 2 points 1 year ago (1 children)

Because 1.2.3.4 and 1.02.003.04 both map to the same number.

But 10.20.30.40 and 010.020.030.040 map to different numbers. It's often best to reject IPv4 addresses with leading zeroes to avoid the decimal vs. octal ambiguity.

[–] dannym@lemmy.escapebigtech.info 2 points 1 year ago (1 children)

I don't know why anyone would write their IPs in octal, but fair point

[–] p1mrx@sh.itjust.works 2 points 1 year ago

It's not about how people write them, it's how parsers parse them. IPv4 has been around since 1982, and most parsers interpret leading zeros as octal.

[–] Emma_Gold_Man@lemmy.dbzer0.com 2 points 1 year ago

True enough for database or dictionary storage, but a lot of times things get implemented in arrays where you still wind up with two copies of the same uint32.