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I say double it.
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this post was submitted on 29 Jul 2023
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It'll just be one fewer junctions. 2^n is always one more than the sum of 2^1+...2^(n-1)
I think you have to include 2^0 for that to be true?
e.g 2^0 = 1, 2^1 = 2 2^0 + 2^1 = 1 + 2 = 3, 2^2 = 4 … 7, 8 15,16 31, 32 etc.