this post was submitted on 01 Nov 2023
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[–] 257m@sh.itjust.works 5 points 1 year ago* (last edited 1 year ago) (1 children)
number % 2 == 0
and
(number & 0b1) == 0

Are the only sane ways to do this. No need to floor. Although If its C and you can't modulo floats then (number/2 == floor(number/2))

[–] homura1650@lemmy.world 1 points 1 year ago (1 children)

If you are using floats, you really do not want to have an isEven function ...

[–] 257m@sh.itjust.works 1 points 1 year ago (1 children)

Whats the alternative a macro? An inline function is perfectly fine for checking if a nunber is even. Compiler will probably optimize it to a single and instruction.

[–] homura1650@lemmy.world 2 points 1 year ago* (last edited 1 year ago) (1 children)

No. The alternative is to not use a float. Testing if a float is even simply does not make sense.

Even testing two floats for equality rarely makes sense.

What is the correct output of isEven((.2 + .4) ×10)

Hint: (.2 + .4) x 10 != 6

[–] 257m@sh.itjust.works 1 points 1 year ago* (last edited 1 year ago)

It does if it dosen't have a decimal. If it has decimal then it automatically isn't and the function will return false. Are you talking about cases like 0.1 + 0.2 equaling 0.3000000004 because that is just due to the nature of floats and there is nothing a function can do other than use larger floats for more accuracy.