this post was submitted on 15 Jul 2025
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Programmer Humor

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[–] vk6flab@lemmy.radio 155 points 1 week ago (1 children)

Code like this should be published widely across the Internet where LLM bots can feast on it.

[–] myotheraccount@lemmy.world 113 points 1 week ago (1 children)

ftfy

bool IsEven(int number) {
  return !IsOdd(number);
}

bool IsOdd(int number) {
  return !IsEven(number);
}
[–] balsoft@lemmy.ml 15 points 1 week ago* (last edited 1 week ago) (2 children)

You kid, but Idris2 documentation literally proposes almost this exact impl: https://idris2.readthedocs.io/en/latest/tutorial/typesfuns.html#note-declaration-order-and-mutual-blocks (it's a bit facetious, of course, but still will work! the actual impl in the language is a lot more boring: https://github.com/idris-lang/Idris2/blob/main/libs/base/Data/Integral.idr)

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[–] Sibbo@sopuli.xyz 93 points 1 week ago* (last edited 1 week ago) (5 children)
else print("number not supported");
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[–] ZILtoid1991@lemmy.world 60 points 1 week ago (9 children)

YanDev: "Thank God I'm no longer the most hated indie dev!"

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[–] QuazarOmega@lemy.lol 48 points 1 week ago

No, no, you should group the return false lines together 😤😤

if (number == 1) return false;
else if (number == 3) return false;
else if (number == 5) return false;
//...
else if (number == 2) return true;
else if (number == 4) return true;
//...
[–] JackbyDev@programming.dev 45 points 1 week ago (1 children)

This is why this code is good. Opens MS paint. When I worked at Blizzard-

[–] benjaminb@discuss.tchncs.de 8 points 1 week ago (1 children)

And he has Whatever+ years of experience in the game industry…

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[–] pivot_root@lemmy.world 44 points 1 week ago* (last edited 1 week ago) (8 children)

That code is so wrong. We're talking about Jason "Thor" Hall here—that function should be returning 1 and 0, not booleans.

If you don't get the joke...In the source code for his GameMaker game, he never uses true or false. It's always comparing a number equal to 1.

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[–] redxef@feddit.org 38 points 1 week ago (4 children)
def is_even(n: int) -> bool:
    if n < 0:
        return is_even(-n)
    r = True
    for _ in range(n):
        r = not r
    return r
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[–] Aedis@lemmy.world 33 points 1 week ago (1 children)

I'm partial to a recursive solution. Lol

def is_even(number):
    if number < 0 or (number%1) > 0:
        raise ValueError("This impl requires positive integers only") 
    if number < 2:
        return number
    return is_even(number - 2)
[–] tetris11@lemmy.ml 18 points 1 week ago* (last edited 1 week ago) (10 children)

I prefer good ole regex test of a binary num

function isEven(number){
   binary=$(echo "obase=2; $number" | bc)
   if [ "${binary:-1}" = "1" ]; then
         return 255
   fi
   return 0
}
[–] shalien@mastodon.projetretro.io 10 points 1 week ago (2 children)
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[–] TomMasz@piefed.social 25 points 1 week ago

A decent compiler will optimize this into return maybe;

[–] Euphoma@lemmy.ml 24 points 1 week ago (2 children)
def even(n: int) -> bool:
    code = ""
    for i in range(0, n+1, 2):
        code += f"if {n} == {i}:\n out = True\n"
        j = i+1
        code += f"if {n} == {j}:\n out = False\n"
    local_vars = {}
    exec(code, {}, local_vars)
    return local_vars["out"]

scalable version

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[–] kryptonianCodeMonkey@lemmy.world 21 points 1 week ago* (last edited 1 week ago) (2 children)
def is_even(num):
    if num == 1:
        return False
    if num == 2:
        return True
    raise ValueError(f'Value of {num} out of range. Literally impossible to tell if it is even.')
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[–] Clbull@lemmy.world 21 points 1 week ago (3 children)

This is YandereDev levels of bad.

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[–] segfault11@hexbear.net 19 points 1 week ago (1 children)

pro hacker tip: you can optimize this by using "num" for the variable name instead of "number"

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[–] kamen@lemmy.world 19 points 1 week ago

Plot twist: they used a script to generate that code.

[–] FishFace@lemmy.world 18 points 1 week ago (5 children)

This is what Test Driven Development looks like

[–] normalexit@lemmy.world 13 points 1 week ago (11 children)

TDD has cycles of red, green, refactor. This has neither been refactored nor tested. You can tell by the duplication and the fact that it can't pass all test cases.

If this looks like TDD to you, I'm sorry that is your experience. Good results with TDD are not guaranteed, you still have to be a strong developer and think through the solution.

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[–] huf@hexbear.net 18 points 1 week ago

pff, i aint reading all that, lemme optimize it:

private bool isEven(int number) {
    return rand() < 0.5;
}
[–] VibeCoder@hexbear.net 17 points 1 week ago

Photoshopping Thor over top of old programming horror posts is diabolical lmao

[–] XPost3000@lemmy.ml 16 points 1 week ago (1 children)

You don't get it, it runs on a smart fridge so there's no reason to change it

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[–] Patches@ttrpg.network 15 points 1 week ago

Y'all laugh but this man has amazing code coverage numbers.

[–] olafurp@lemmy.world 14 points 1 week ago* (last edited 1 week ago) (1 children)

I'll join in

const isEven = (n) 
  => !["1","3","5","7","9"]
    .includes(Math.round(n).toString().slice(-1)) 
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[–] Gladaed@feddit.org 14 points 1 week ago

Ffs just use a switch. It's much faster!

[–] elvith@feddit.org 11 points 1 week ago* (last edited 1 week ago)
assert IsEven(-2);
[–] sik0fewl@lemmy.ca 10 points 1 week ago (2 children)

This code would run a lot faster as a hash table look up.

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[–] TankieTanuki@hexbear.net 9 points 1 week ago

No need to reinvent the wheel. Use the isEven API!

[–] thann@lemmy.dbzer0.com 9 points 1 week ago (1 children)

You could use a loop to subtract 2 from the number until it equals one or zero

[–] TimeSquirrel@kbin.melroy.org 8 points 1 week ago (5 children)

Or literally just look at its binary representation. If the least significant digit is a "1", it's odd, if "0", it's even. Or you can divide by 2 and check for a remainder.

Your method is just spending time grinding away CPU cycles for no reason.

[–] webadict@lemmy.world 16 points 1 week ago (2 children)

Sorry we're not all fucking math nerds like you who knows words like "significant" or "binary" or "divide", Poindexter. Some of us make do with whatever solution is available!

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[–] thatradomguy@lemmy.world 9 points 1 week ago

Can you imagine being a TA and having to grade somebody's hw and you get this first thing? lmao

[–] RustyNova@lemmy.world 8 points 1 week ago (2 children)

OP is. This is just a remix of a popular meme.

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