Ask Lemmy

Are you saying you don’t believe it? Because you explained why it works pretty well. When the host opens the door, they will always open a non-winning door, so it doesn’t affect the odds at all. There is still a 1:3 chance it’s the door you picked, and a 2:3 that it’s one of the other 2. All the host did is showed you which one it wasn’t behind, and that means the odds of that remaining door is 2:3

This problem doesn't make any sense.

If one wrong door is always opened, your chance was never 1/3 to begin with, so you are thinking about this problem with the wrong premise, making it hard to grasp. You were just assuming it was 1/3 because you didn't know one door would be taken away.

As soon as the wrong door is opened, your odds are never 1/3 nor 2/3. It's 1/2 because there's only two doors. What did you think the number after / stood for?

EDIT: Now I've tried to look through the examples in the article, and it honestly just makes it worse.

The example about picking a door at 1/1000, and then Monty removing 998 of the doors, leaving two doors, therefore making it more likely you should pick the one Monty left open, is also stupid - because it's not comparable.

The above example is true. The likelihood of Monty being right is much higher.

But your pick is never 1/1000 when there's only 3 doors, making the example not compatible with the other. The 1000 door example is not wrong - you just can't compare them.

And now to explain why it's different:

In the 3 door example, your "pick power" is 1. Means you can pick 1 door. Montys "pick power" is also 1, making you both equally strong.

This means that you picking a door gives as much intel as Monty picking a door does. No matter what, you will always be left with 1 door not being picked.

Now you look at the 2 doors. The one you picked, and the one nobody did. Now this problem suggests that Monty has given you new information because he removed a door, but he didn't give you that, and here's why:

The problem suggests that Monty gives you intel by removing a door in a 1/3 scenario. But he doesn't. That's an illusion.

From Montys perspective, he only has 2 doors to pick from, because he can NEVER remove yours, no matter what you picked.

Now Monty has made his choice, and this is where we turn the game around making it clear it was a 1/2 choice all along.

Because the thing you are picking between is not the doors anymore. It was never about the doors.

You are picking between if Monty is bluffing or not.

Let's say you always pick door 1 as your first option. Monty will always remove 2 or 3. Either Monty removes door 2 or 3 because he helps you, or he's doing it because he's bluffing.

If you didn't get any more help, this WOULD'VE been a 1/3. You'd have to choose between if Monty bluffed at door 2 or he bluffed at door 3, or he bluffed at both, because it was your door.

But then Monty goes ahead and removes a door, let's say 3 (or 2 if you want, it doesn't matter). He tells you it's not that one. Now you have to choose if he's bluffing at door 2 or he's bluffing at your door.

You now have a 1/2 to call his bluff.

Monty was the enemy all along - not the doors.

The Monty Hall problem has always bothered me when considering it on the basis of 3 doors. However when the concept is extended to 100 doors, and 98 are opened, it starts to click for me that of course the odds arent 50/50. It's much more obvious that the prize was in the field (and the odds shift to reflect that)